z^2=(x^2)/2-(y^2)/3-2

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Solution for z^2=(x^2)/2-(y^2)/3-2 equation: 


x in (-oo:+oo)

z^2 = (x^2)/2-((y^2)/3)-2 // - (x^2)/2-((y^2)/3)-2

(y^2)/3-((x^2)/2)+z^2+2 = 0

-1/2*x^2 = -(1/3*y^2+z^2+2) // : -1/2

x^2 = 2*(1/3*y^2+z^2+2)

x^2 = 2*(1/3*y^2+z^2+2) // ^ 1/2

abs(x) = 2^(1/2)*(1/3*y^2+z^2+2)^(1/2)

x = 2^(1/2)*(1/3*y^2+z^2+2)^(1/2) or x = -(2^(1/2)*(1/3*y^2+z^2+2)^(1/2))

x in { 2^(1/2)*(1/3*y^2+z^2+2)^(1/2), -(2^(1/2)*(1/3*y^2+z^2+2)^(1/2)) }

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